What are the solutions to the equation x^2+1=3x^2-13 ?

The solutions to the equation x^2+1=3x^2-13 are x=sqrt(7),x=-sqrt(7)

Find the zeros of x^2+1=3x^2-13

The zeros of x^2+1=3x^2-13 are x=sqrt(7),x=-sqrt(7)

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x^{2} + 1 = 3 x^{2} - 13

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

x^{2} + 1 = 3 x^{2} - 13

Move

1

to the right side

x^{2} = 3 x^{2} - 14

Move

3 x^{2}

to the left side

- 2 x^{2} = - 14

Divide both sides by

- 2

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

x, x^{2} + y^{2} = 1

4 x^{2} - 40 x - 12 = 0

- 2 x^{2} - 4 x = 0

3 x^{2} - 5 x - 3 = 0

x, x^{2} + y^{2} - 4 x - 6 y + 13 = 0

What are the solutions to the equation x^2+1=3x^2-13 ?
The solutions to the equation x^2+1=3x^2-13 are x=sqrt(7),x=-sqrt(7)
Find the zeros of x^2+1=3x^2-13
The zeros of x^2+1=3x^2-13 are x=sqrt(7),x=-sqrt(7)