What are the solutions to the equation m^2+8m+15=0 ?

The solutions to the equation m^2+8m+15=0 are m=-3,m=-5

Find the zeros of m^2+8m+15=0

The zeros of m^2+8m+15=0 are m=-3,m=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 8 m + 15 = 0

m = - 3, m = - 5

Solution steps

m^{2} + 8 m + 15 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

m_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 8 + 2}{2 \cdot 1}, m_{2} = \frac{- 8 - 2}{2 \cdot 1}

m = \frac{- 8 + 2}{2 \cdot 1} : - 3

m = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

m = - 3, m = - 5

x^{2} - 16 x - 36 = 0

3 x^{2} - 6 x - 5

3 x^{2} + 2 x = - 7

x^{2} - 6 x + 5

x^{2} + 7 x + 36 = 0

What are the solutions to the equation m^2+8m+15=0 ?
The solutions to the equation m^2+8m+15=0 are m=-3,m=-5
Find the zeros of m^2+8m+15=0
The zeros of m^2+8m+15=0 are m=-3,m=-5