What are the solutions to the equation a^2x^2-2ax-3=0 ?

The solutions to the equation a^2x^2-2ax-3=0 are x= 3/a ,x=-1/a ;\quad a\ne 0

Find the zeros of a^2x^2-2ax-3=0

The zeros of a^2x^2-2ax-3=0 are x= 3/a ,x=-1/a ;\quad a\ne 0

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a^{2} x^{2} - 2 a x - 3 = 0

x = \frac{3}{a}, x = - \frac{1}{a}; a \neq = 0

Solution steps

a^{2} x^{2} - 2 a x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 a ) \pm ( - 2 a ) ^{2} - 4 a ^{2} ( - 3 )}{2 a ^{2}}

Simplify

(- 2 a)^{2} - 4 a^{2} (- 3) : 4 a

x_{1, 2} = \frac{- ( - 2 a ) \pm 4 a}{2 a ^{2}}; a \neq = 0

Separate the solutions

x_{1} = \frac{- ( - 2 a ) + 4 a}{2 a ^{2}}, x_{2} = \frac{- ( - 2 a ) - 4 a}{2 a ^{2}}

x = \frac{- ( - 2 a ) + 4 a}{2 a ^{2}} : \frac{3}{a}

x = \frac{- ( - 2 a ) - 4 a}{2 a ^{2}} : - \frac{1}{a}

The solutions to the quadratic equation are:

x = \frac{3}{a}, x = - \frac{1}{a}; a \neq = 0

2 z^{2} + 2 z - 1 = 0

(x + 2)^{3} - (x - 1)^{3} = x (3 x + 4) + 8

x^{2} + (x + 3)^{2} = 1 5^{2}

(6 + 2 x) (10 + 2 x) - 60 = 36

3 a x^{2} + 2 b x + c = 0

What are the solutions to the equation a^2x^2-2ax-3=0 ?
The solutions to the equation a^2x^2-2ax-3=0 are x= 3/a ,x=-1/a ;\quad a\ne 0
Find the zeros of a^2x^2-2ax-3=0
The zeros of a^2x^2-2ax-3=0 are x= 3/a ,x=-1/a ;\quad a\ne 0