What are the solutions to the equation (x+2)^2-(2x-5)/3 =3 ?

The solutions to the equation (x+2)^2-(2x-5)/3 =3 are x=-4/3 ,x=-2

Find the zeros of (x+2)^2-(2x-5)/3 =3

The zeros of (x+2)^2-(2x-5)/3 =3 are x=-4/3 ,x=-2

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(x + 2)^{2} - \frac{2 x - 5}{3} = 3

x = - \frac{4}{3}, x = - 2

Decimal Notation

x = - 1.33333 \dots, x = - 2

Solution steps

(x + 2)^{2} - \frac{2 x - 5}{3} = 3

Multiply both sides by

3

3 (x + 2)^{2} - (2 x - 5) = 9

Expand

3 (x + 2)^{2} - (2 x - 5) : 3 x^{2} + 10 x + 17

3 x^{2} + 10 x + 17 = 9

Move

9

to the left side

3 x^{2} + 10 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 \cdot 8 = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 2}{2 \cdot 3}, x_{2} = \frac{- 10 - 2}{2 \cdot 3}

x = \frac{- 10 + 2}{2 \cdot 3} : - \frac{4}{3}

x = \frac{- 10 - 2}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = - 2

10 - 2 x^{2} = - 98

x^{2} - 30 x + 50 = 0

3 c^{2} + 7 c + 2 = 2 c^{2}

x^{2} + 10 x - 25 = 4 x + 2

s^{2} + s + 1

What are the solutions to the equation (x+2)^2-(2x-5)/3 =3 ?
The solutions to the equation (x+2)^2-(2x-5)/3 =3 are x=-4/3 ,x=-2
Find the zeros of (x+2)^2-(2x-5)/3 =3
The zeros of (x+2)^2-(2x-5)/3 =3 are x=-4/3 ,x=-2