What are the solutions to the equation 5x^2+4x-15=0 ?

The solutions to the equation 5x^2+4x-15=0 are x=(-2+sqrt(79))/5 ,x=-(2+sqrt(79))/5

Find the zeros of 5x^2+4x-15=0

The zeros of 5x^2+4x-15=0 are x=(-2+sqrt(79))/5 ,x=-(2+sqrt(79))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + 4 x - 15 = 0

x = \frac{- 2 + 79}{5}, x = - \frac{2 + 79}{5}

Decimal Notation

x = 1.37763 \dots, x = - 2.17763 \dots

Solution steps

5 x^{2} + 4 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 ( - 15 )}{2 \cdot 5}

4^{2} - 4 \cdot 5 (- 15) = 279

x_{1, 2} = \frac{- 4 \pm 2 79}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 2 79}{2 \cdot 5}, x_{2} = \frac{- 4 - 2 79}{2 \cdot 5}

x = \frac{- 4 + 2 79}{2 \cdot 5} : \frac{- 2 + 79}{5}

x = \frac{- 4 - 2 79}{2 \cdot 5} : - \frac{2 + 79}{5}

The solutions to the quadratic equation are:

x = \frac{- 2 + 79}{5}, x = - \frac{2 + 79}{5}

s^{2} + 2 = 0

8 x^{2} - 11 x = - 3

5 (5 x + 2)^{2} - 15 = 30

(2 x - 3)^{2} = 16

z^{2} + 9 = 0

What are the solutions to the equation 5x^2+4x-15=0 ?
The solutions to the equation 5x^2+4x-15=0 are x=(-2+sqrt(79))/5 ,x=-(2+sqrt(79))/5
Find the zeros of 5x^2+4x-15=0
The zeros of 5x^2+4x-15=0 are x=(-2+sqrt(79))/5 ,x=-(2+sqrt(79))/5