What are the solutions to the equation 5b^2+3b-4=0 ?

The solutions to the equation 5b^2+3b-4=0 are b=(-3+sqrt(89))/(10),b=(-3-sqrt(89))/(10)

Find the zeros of 5b^2+3b-4=0

The zeros of 5b^2+3b-4=0 are b=(-3+sqrt(89))/(10),b=(-3-sqrt(89))/(10)

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5 b^{2} + 3 b - 4 = 0

b = \frac{- 3 + 89}{10}, b = \frac{- 3 - 89}{10}

Decimal Notation

b = 0.64339 \dots, b = - 1.24339 \dots

Solution steps

5 b^{2} + 3 b - 4 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

3^{2} - 4 \cdot 5 (- 4) = 89

b_{1, 2} = \frac{- 3 \pm 89}{2 \cdot 5}

Separate the solutions

b_{1} = \frac{- 3 + 89}{2 \cdot 5}, b_{2} = \frac{- 3 - 89}{2 \cdot 5}

b = \frac{- 3 + 89}{2 \cdot 5} : \frac{- 3 + 89}{10}

b = \frac{- 3 - 89}{2 \cdot 5} : \frac{- 3 - 89}{10}

The solutions to the quadratic equation are:

b = \frac{- 3 + 89}{10}, b = \frac{- 3 - 89}{10}

x^{2} - 13 x + 110 = 160 - 9 x

x^{2} - 2 x + a = 0

\frac{y ^{2}}{3} = \frac{y ^{2}}{6} + 2

(3 x + 5)^{2} + 5 (3 x + 5) + 6 = 0

- 5 c^{2} + c - 18 = - 6 c^{2}

What are the solutions to the equation 5b^2+3b-4=0 ?
The solutions to the equation 5b^2+3b-4=0 are b=(-3+sqrt(89))/(10),b=(-3-sqrt(89))/(10)
Find the zeros of 5b^2+3b-4=0
The zeros of 5b^2+3b-4=0 are b=(-3+sqrt(89))/(10),b=(-3-sqrt(89))/(10)