What are the solutions to the equation (3x+5)^2+5(3x+5)+6=0 ?

The solutions to the equation (3x+5)^2+5(3x+5)+6=0 are x=-7/3 ,x=-8/3

Find the zeros of (3x+5)^2+5(3x+5)+6=0

The zeros of (3x+5)^2+5(3x+5)+6=0 are x=-7/3 ,x=-8/3

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(3 x + 5)^{2} + 5 (3 x + 5) + 6 = 0

x = - \frac{7}{3}, x = - \frac{8}{3}

Decimal Notation

x = - 2.33333 \dots, x = - 2.66666 \dots

Solution steps

(3 x + 5)^{2} + 5 (3 x + 5) + 6 = 0

Expand

(3 x + 5)^{2} + 5 (3 x + 5) + 6 : 9 x^{2} + 45 x + 56

9 x^{2} + 45 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 45 \pm 4 5 ^{2} - 4 \cdot 9 \cdot 56}{2 \cdot 9}

4 5^{2} - 4 \cdot 9 \cdot 56 = 3

x_{1, 2} = \frac{- 45 \pm 3}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 45 + 3}{2 \cdot 9}, x_{2} = \frac{- 45 - 3}{2 \cdot 9}

x = \frac{- 45 + 3}{2 \cdot 9} : - \frac{7}{3}

x = \frac{- 45 - 3}{2 \cdot 9} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = - \frac{7}{3}, x = - \frac{8}{3}

- 5 c^{2} + c - 18 = - 6 c^{2}

(2 x - 1) (x + 2) = (x + 3) (x + 1)

y^{2} - 2 y - 1 = 0

5 x^{2} = 7 x + 7

16 (5 x - 3)^{2} - 28 = - 19

What are the solutions to the equation (3x+5)^2+5(3x+5)+6=0 ?
The solutions to the equation (3x+5)^2+5(3x+5)+6=0 are x=-7/3 ,x=-8/3
Find the zeros of (3x+5)^2+5(3x+5)+6=0
The zeros of (3x+5)^2+5(3x+5)+6=0 are x=-7/3 ,x=-8/3