What are the solutions to the equation 16(5x-3)^2-28=-19 ?

The solutions to the equation 16(5x-3)^2-28=-19 are x= 3/4 ,x= 9/20

Find the zeros of 16(5x-3)^2-28=-19

The zeros of 16(5x-3)^2-28=-19 are x= 3/4 ,x= 9/20

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16 (5 x - 3)^{2} - 28 = - 19

x = \frac{3}{4}, x = \frac{9}{20}

Decimal Notation

x = 0.75, x = 0.45

Solution steps

16 (5 x - 3)^{2} - 28 = - 19

Move

28

to the right side

16 (5 x - 3)^{2} = 9

Divide both sides by

16

(5 x - 3)^{2} = \frac{9}{16}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 3 = \frac{9}{16} : x = \frac{3}{4}

Solve

5 x - 3 = - \frac{9}{16} : x = \frac{9}{20}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = \frac{9}{20}

(x + 12)^{2} = 9

(a - 3)^{2} = 5 - 10 a

w^{2} - 4 w - 77 = 0

9 x^{2} + 16 = 24 x

n^{2} - n - 5 = - 2 n^{2}

What are the solutions to the equation 16(5x-3)^2-28=-19 ?
The solutions to the equation 16(5x-3)^2-28=-19 are x= 3/4 ,x= 9/20
Find the zeros of 16(5x-3)^2-28=-19
The zeros of 16(5x-3)^2-28=-19 are x= 3/4 ,x= 9/20