What are the solutions to the equation (a-3)^2=5-10a ?

The solutions to the equation (a-3)^2=5-10a are a=-2

Find the zeros of (a-3)^2=5-10a

The zeros of (a-3)^2=5-10a are a=-2

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(a - 3)^{2} = 5 - 10 a

a = - 2

Solution steps

(a - 3)^{2} = 5 - 10 a

Expand

(a - 3)^{2} : a^{2} - 6 a + 9

a^{2} - 6 a + 9 = 5 - 10 a

Move

10 a

to the left side

a^{2} + 4 a + 9 = 5

Move

5

to the left side

a^{2} + 4 a + 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

a_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

a = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

a = - 2

The solution to the quadratic equation is:

a = - 2

w^{2} - 4 w - 77 = 0

9 x^{2} + 16 = 24 x

n^{2} - n - 5 = - 2 n^{2}

n^{2} - 5 n + 6 = 0

x^{2} - 64 x = - 1.24

What are the solutions to the equation (a-3)^2=5-10a ?
The solutions to the equation (a-3)^2=5-10a are a=-2
Find the zeros of (a-3)^2=5-10a
The zeros of (a-3)^2=5-10a are a=-2