What are the solutions to the equation solvefor x,z=2x^2+3y^2 ?

The solutions to the equation solvefor x,z=2x^2+3y^2 are x=sqrt((z-3y^2)/2),x=-sqrt((z-3y^2)/2)

Find the zeros of solvefor x,z=2x^2+3y^2

The zeros of solvefor x,z=2x^2+3y^2 are x=sqrt((z-3y^2)/2),x=-sqrt((z-3y^2)/2)

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solve for

x, z = 2 x^{2} + 3 y^{2}

x = \frac{z - 3 y ^{2}}{2}, x = - \frac{z - 3 y ^{2}}{2}

Solution steps

z = 2 x^{2} + 3 y^{2}

Switch sides

2 x^{2} + 3 y^{2} = z

Move

3 y^{2}

to the right side

2 x^{2} = z - 3 y^{2}

Divide both sides by

2

x^{2} = \frac{z - 3 y ^{2}}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{z - 3 y ^{2}}{2}, x = - \frac{z - 3 y ^{2}}{2}

3 (2 w - 3)^{2} - 5 = 70

x^{2} - 2 x = - x^{2} + 4 x

t, f (t - 3) = - (t - 3)^{2} + 6 (t - 3) - 11

8 x^{2} + 128 = 0

y, x^{2} + y^{2} = 25

What are the solutions to the equation solvefor x,z=2x^2+3y^2 ?
The solutions to the equation solvefor x,z=2x^2+3y^2 are x=sqrt((z-3y^2)/2),x=-sqrt((z-3y^2)/2)
Find the zeros of solvefor x,z=2x^2+3y^2
The zeros of solvefor x,z=2x^2+3y^2 are x=sqrt((z-3y^2)/2),x=-sqrt((z-3y^2)/2)