What are the solutions to the equation x^2+17x+9=13x-3 ?

The solutions to the equation x^2+17x+9=13x-3 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i

Find the zeros of x^2+17x+9=13x-3

The zeros of x^2+17x+9=13x-3 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i

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x^{2} + 17 x + 9 = 13 x - 3

x = - 2 + 22 i, x = - 2 - 22 i

Solution steps

x^{2} + 17 x + 9 = 13 x - 3

Move

3

to the left side

x^{2} + 17 x + 12 = 13 x

Move

13 x

to the left side

x^{2} + 4 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 12 : 42 i

x_{1, 2} = \frac{- 4 \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 2 i}{2 \cdot 1}

x = \frac{- 4 + 4 2 i}{2 \cdot 1} : - 2 + 22 i

x = \frac{- 4 - 4 2 i}{2 \cdot 1} : - 2 - 22 i

The solutions to the quadratic equation are:

x = - 2 + 22 i, x = - 2 - 22 i

3 x^{2} - 20 x + 12 = 0

4 x^{2} - 7 x + 1 = 0

5 x^{2} + 12 = 3 x^{2} - 20

x^{2} - 9 x - 580 = 0

25 (x^{2} + 1) - 13 = 13

What are the solutions to the equation x^2+17x+9=13x-3 ?
The solutions to the equation x^2+17x+9=13x-3 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i
Find the zeros of x^2+17x+9=13x-3
The zeros of x^2+17x+9=13x-3 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i