What are the solutions to the equation x^2+100x+2500=0 ?

The solutions to the equation x^2+100x+2500=0 are x=-50

Find the zeros of x^2+100x+2500=0

The zeros of x^2+100x+2500=0 are x=-50

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x^{2} + 100 x + 2500 = 0

x = - 50

Solution steps

x^{2} + 100 x + 2500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 \cdot 1 \cdot 2500}{2 \cdot 1}

10 0^{2} - 4 \cdot 1 \cdot 2500 = 0

x_{1, 2} = \frac{- 100 \pm 0}{2 \cdot 1}

x = \frac{- 100}{2 \cdot 1}

\frac{- 100}{2 \cdot 1} = - 50

x = - 50

The solution to the quadratic equation is:

x = - 50

x^{2} - 19 x = 0

x^{2} - 6 x + 9 = 0

2 x^{2} - 2 x + 4 = 0

x^{2} + 22 x + 121 = 169

2 z^{2} + 9 z = 5

What are the solutions to the equation x^2+100x+2500=0 ?
The solutions to the equation x^2+100x+2500=0 are x=-50
Find the zeros of x^2+100x+2500=0
The zeros of x^2+100x+2500=0 are x=-50