What are the solutions to the equation 2z^2+9z=5 ?

The solutions to the equation 2z^2+9z=5 are z= 1/2 ,z=-5

Find the zeros of 2z^2+9z=5

The zeros of 2z^2+9z=5 are z= 1/2 ,z=-5

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2 z^{2} + 9 z = 5

z = \frac{1}{2}, z = - 5

Decimal Notation

z = 0.5, z = - 5

Solution steps

2 z^{2} + 9 z = 5

Move

5

to the left side

2 z^{2} + 9 z - 5 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 5) = 11

z_{1, 2} = \frac{- 9 \pm 11}{2 \cdot 2}

Separate the solutions

z_{1} = \frac{- 9 + 11}{2 \cdot 2}, z_{2} = \frac{- 9 - 11}{2 \cdot 2}

z = \frac{- 9 + 11}{2 \cdot 2} : \frac{1}{2}

z = \frac{- 9 - 11}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

z = \frac{1}{2}, z = - 5

t, d = v t + \frac{1}{2} a t^{2}

2 x^{2} - 20 x + 89 = - 87

x^{2} - x = 4

(x - 10)^{2} = 100

x^{2} + 7 x = x - 10

What are the solutions to the equation 2z^2+9z=5 ?
The solutions to the equation 2z^2+9z=5 are z= 1/2 ,z=-5
Find the zeros of 2z^2+9z=5
The zeros of 2z^2+9z=5 are z= 1/2 ,z=-5