What are the solutions to the equation x^2+7x=x-10 ?

The solutions to the equation x^2+7x=x-10 are x=-3+i,x=-3-i

Find the zeros of x^2+7x=x-10

The zeros of x^2+7x=x-10 are x=-3+i,x=-3-i

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x^{2} + 7 x = x - 10

x = - 3 + i, x = - 3 - i

Solution steps

x^{2} + 7 x = x - 10

Move

10

to the left side

x^{2} + 7 x + 10 = x

Move

x

to the left side

x^{2} + 6 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 10 : 2 i

x_{1, 2} = \frac{- 6 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 i}{2 \cdot 1}

x = \frac{- 6 + 2 i}{2 \cdot 1} : - 3 + i

x = \frac{- 6 - 2 i}{2 \cdot 1} : - 3 - i

The solutions to the quadratic equation are:

x = - 3 + i, x = - 3 - i

x^{2} + 4 x + 25 = 0

x^{2} + a x + b = 0

r^{2} = 5

x^{2} + 7 x - 78 = 0

338 - 6 x^{2} = 0

What are the solutions to the equation x^2+7x=x-10 ?
The solutions to the equation x^2+7x=x-10 are x=-3+i,x=-3-i
Find the zeros of x^2+7x=x-10
The zeros of x^2+7x=x-10 are x=-3+i,x=-3-i