What are the solutions to the equation x^2+7x-78=0 ?

The solutions to the equation x^2+7x-78=0 are x=6,x=-13

Find the zeros of x^2+7x-78=0

The zeros of x^2+7x-78=0 are x=6,x=-13

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x^{2} + 7 x - 78 = 0

x = 6, x = - 13

Solution steps

x^{2} + 7 x - 78 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 78 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 78) = 19

x_{1, 2} = \frac{- 7 \pm 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 19}{2 \cdot 1}, x_{2} = \frac{- 7 - 19}{2 \cdot 1}

x = \frac{- 7 + 19}{2 \cdot 1} : 6

x = \frac{- 7 - 19}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 6, x = - 13

338 - 6 x^{2} = 0

x, x^{2} + y^{2} = 2 x y

a^{2} + 5 a - 8 = 0

x^{2} = 2

x^{2} + 14 x - 5 = 0

What are the solutions to the equation x^2+7x-78=0 ?
The solutions to the equation x^2+7x-78=0 are x=6,x=-13
Find the zeros of x^2+7x-78=0
The zeros of x^2+7x-78=0 are x=6,x=-13