What are the solutions to the equation d(7d-6)+4=0 ?

The solutions to the equation d(7d-6)+4=0 are d= 3/7+i(sqrt(19))/7 ,d= 3/7-i(sqrt(19))/7

Find the zeros of d(7d-6)+4=0

The zeros of d(7d-6)+4=0 are d= 3/7+i(sqrt(19))/7 ,d= 3/7-i(sqrt(19))/7

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d (7 d - 6) + 4 = 0

d = \frac{3}{7} + i \frac{19}{7}, d = \frac{3}{7} - i \frac{19}{7}

Solution steps

d (7 d - 6) + 4 = 0

Expand

d (7 d - 6) + 4 : 7 d^{2} - 6 d + 4

7 d^{2} - 6 d + 4 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 7 \cdot 4}{2 \cdot 7}

Simplify

(- 6)^{2} - 4 \cdot 7 \cdot 4 : 219 i

d_{1, 2} = \frac{- ( - 6 ) \pm 2 19 i}{2 \cdot 7}

Separate the solutions

d_{1} = \frac{- ( - 6 ) + 2 19 i}{2 \cdot 7}, d_{2} = \frac{- ( - 6 ) - 2 19 i}{2 \cdot 7}

d = \frac{- ( - 6 ) + 2 19 i}{2 \cdot 7} : \frac{3}{7} + i \frac{19}{7}

d = \frac{- ( - 6 ) - 2 19 i}{2 \cdot 7} : \frac{3}{7} - i \frac{19}{7}

The solutions to the quadratic equation are:

d = \frac{3}{7} + i \frac{19}{7}, d = \frac{3}{7} - i \frac{19}{7}

2 x^{2} - 7 x - 13 = 0

x^{2} - 3 x + 9

x^{2} + 15 x - 16 = 0

2 x^{2} - 9 x - 4 = 0

4 x^{2} + 16 x - 1

What are the solutions to the equation d(7d-6)+4=0 ?
The solutions to the equation d(7d-6)+4=0 are d= 3/7+i(sqrt(19))/7 ,d= 3/7-i(sqrt(19))/7
Find the zeros of d(7d-6)+4=0
The zeros of d(7d-6)+4=0 are d= 3/7+i(sqrt(19))/7 ,d= 3/7-i(sqrt(19))/7