What are the solutions to the equation 4x^2+4x-5=0 ?

The solutions to the equation 4x^2+4x-5=0 are x=(-1+sqrt(6))/2 ,x=-(1+sqrt(6))/2

Find the zeros of 4x^2+4x-5=0

The zeros of 4x^2+4x-5=0 are x=(-1+sqrt(6))/2 ,x=-(1+sqrt(6))/2

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4 x^{2} + 4 x - 5 = 0

x = \frac{- 1 + 6}{2}, x = - \frac{1 + 6}{2}

Decimal Notation

x = 0.72474 \dots, x = - 1.72474 \dots

Solution steps

4 x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 5) = 46

x_{1, 2} = \frac{- 4 \pm 4 6}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 4 6}{2 \cdot 4}, x_{2} = \frac{- 4 - 4 6}{2 \cdot 4}

x = \frac{- 4 + 4 6}{2 \cdot 4} : \frac{- 1 + 6}{2}

x = \frac{- 4 - 4 6}{2 \cdot 4} : - \frac{1 + 6}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 6}{2}, x = - \frac{1 + 6}{2}

- 3 x^{2} - 6 = 0

r^{2} - 4 r = 0

- x^{2} - 2 x + 3

5 - 6 x - x^{2}

(2 x + 3)^{2} = 36

What are the solutions to the equation 4x^2+4x-5=0 ?
The solutions to the equation 4x^2+4x-5=0 are x=(-1+sqrt(6))/2 ,x=-(1+sqrt(6))/2
Find the zeros of 4x^2+4x-5=0
The zeros of 4x^2+4x-5=0 are x=(-1+sqrt(6))/2 ,x=-(1+sqrt(6))/2