What are the solutions to the equation -2x^2+3x+1=0 ?

The solutions to the equation -2x^2+3x+1=0 are x=-(-3+sqrt(17))/4 ,x=(3+sqrt(17))/4

Find the zeros of -2x^2+3x+1=0

The zeros of -2x^2+3x+1=0 are x=-(-3+sqrt(17))/4 ,x=(3+sqrt(17))/4

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- 2 x^{2} + 3 x + 1 = 0

x = - \frac{- 3 + 17}{4}, x = \frac{3 + 17}{4}

Decimal Notation

x = - 0.28077 \dots, x = 1.78077 \dots

Solution steps

- 2 x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) \cdot 1}{2 ( - 2 )}

3^{2} - 4 (- 2) \cdot 1 = 17

x_{1, 2} = \frac{- 3 \pm 17}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 17}{2 ( - 2 )}, x_{2} = \frac{- 3 - 17}{2 ( - 2 )}

x = \frac{- 3 + 17}{2 ( - 2 )} : - \frac{- 3 + 17}{4}

x = \frac{- 3 - 17}{2 ( - 2 )} : \frac{3 + 17}{4}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 17}{4}, x = \frac{3 + 17}{4}

(x - 2)^{2} + 46 = 47

0.02 w^{2} - 0.3 w = 20

(x - 1)^{2} = 36

d^{2} + 20 = - 300

- 5 (3 x^{2} + 5 x + b) = a x^{2} - 25 x + 45

What are the solutions to the equation -2x^2+3x+1=0 ?
The solutions to the equation -2x^2+3x+1=0 are x=-(-3+sqrt(17))/4 ,x=(3+sqrt(17))/4
Find the zeros of -2x^2+3x+1=0
The zeros of -2x^2+3x+1=0 are x=-(-3+sqrt(17))/4 ,x=(3+sqrt(17))/4