What are the solutions to the equation z^2-5z+4=0 ?

The solutions to the equation z^2-5z+4=0 are z=4,z=1

Find the zeros of z^2-5z+4=0

The zeros of z^2-5z+4=0 are z=4,z=1

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z^{2} - 5 z + 4 = 0

z = 4, z = 1

Solution steps

z^{2} - 5 z + 4 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

z_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, z_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

z = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

z = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

z = 4, z = 1

4 x^{2} + 8 x + 5 = 0

n^{2} - 22 n + 102 = 0

12 x^{2} - 520 x + 4000 = 0

x = 5 x^{2}

(x + 2)^{2} = 64

What are the solutions to the equation z^2-5z+4=0 ?
The solutions to the equation z^2-5z+4=0 are z=4,z=1
Find the zeros of z^2-5z+4=0
The zeros of z^2-5z+4=0 are z=4,z=1