What are the solutions to the equation -2x^2+6=0 ?

The solutions to the equation -2x^2+6=0 are x=sqrt(3),x=-sqrt(3)

Find the zeros of -2x^2+6=0

The zeros of -2x^2+6=0 are x=sqrt(3),x=-sqrt(3)

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- 2 x^{2} + 6 = 0

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

- 2 x^{2} + 6 = 0

Move

6

to the right side

- 2 x^{2} = - 6

Divide both sides by

- 2

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

x, x^{2} - 2 x - 3 = 0

p^{2} - 16 p + 13 = - 3 p^{2}

(3 x - 4) (x + 5) = 0

x (x + 1) = 30

\frac{1}{3} x^{2} + \frac{5}{6} x = 0

What are the solutions to the equation -2x^2+6=0 ?
The solutions to the equation -2x^2+6=0 are x=sqrt(3),x=-sqrt(3)
Find the zeros of -2x^2+6=0
The zeros of -2x^2+6=0 are x=sqrt(3),x=-sqrt(3)