What are the solutions to the equation -2x^2-40x-224=0 ?

The solutions to the equation -2x^2-40x-224=0 are x=-10-2sqrt(3)i,x=-10+2sqrt(3)i

Find the zeros of -2x^2-40x-224=0

The zeros of -2x^2-40x-224=0 are x=-10-2sqrt(3)i,x=-10+2sqrt(3)i

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- 2 x^{2} - 40 x - 224 = 0

x = - 10 - 23 i, x = - 10 + 23 i

Solution steps

- 2 x^{2} - 40 x - 224 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 ( - 2 ) ( - 224 )}{2 ( - 2 )}

Simplify

(- 40)^{2} - 4 (- 2) (- 224) : 83 i

x_{1, 2} = \frac{- ( - 40 ) \pm 8 3 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 8 3 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 40 ) - 8 3 i}{2 ( - 2 )}

x = \frac{- ( - 40 ) + 8 3 i}{2 ( - 2 )} : - 10 - 23 i

x = \frac{- ( - 40 ) - 8 3 i}{2 ( - 2 )} : - 10 + 23 i

The solutions to the quadratic equation are:

x = - 10 - 23 i, x = - 10 + 23 i

(3 x + 2) (x - 1) = 3 x

6 x^{2} + x + 1 = 0

2 k^{2} - 37 = 61

x^{2} - 7 = 9

y^{2} + 6 y

What are the solutions to the equation -2x^2-40x-224=0 ?
The solutions to the equation -2x^2-40x-224=0 are x=-10-2sqrt(3)i,x=-10+2sqrt(3)i
Find the zeros of -2x^2-40x-224=0
The zeros of -2x^2-40x-224=0 are x=-10-2sqrt(3)i,x=-10+2sqrt(3)i