What are the solutions to the equation 5x^2+15=17x ?

The solutions to the equation 5x^2+15=17x are x= 17/10+i(sqrt(11))/(10),x= 17/10-i(sqrt(11))/(10)

Find the zeros of 5x^2+15=17x

The zeros of 5x^2+15=17x are x= 17/10+i(sqrt(11))/(10),x= 17/10-i(sqrt(11))/(10)

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5 x^{2} + 15 = 17 x

x = \frac{17}{10} + i \frac{11}{10}, x = \frac{17}{10} - i \frac{11}{10}

Solution steps

5 x^{2} + 15 = 17 x

Move

17 x

to the left side

5 x^{2} + 15 - 17 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 17 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 5 \cdot 15}{2 \cdot 5}

Simplify

(- 17)^{2} - 4 \cdot 5 \cdot 15 : 11 i

x_{1, 2} = \frac{- ( - 17 ) \pm 11 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 11 i}{2 \cdot 5}, x_{2} = \frac{- ( - 17 ) - 11 i}{2 \cdot 5}

x = \frac{- ( - 17 ) + 11 i}{2 \cdot 5} : \frac{17}{10} + i \frac{11}{10}

x = \frac{- ( - 17 ) - 11 i}{2 \cdot 5} : \frac{17}{10} - i \frac{11}{10}

The solutions to the quadratic equation are:

x = \frac{17}{10} + i \frac{11}{10}, x = \frac{17}{10} - i \frac{11}{10}

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x^{2} - 2 x - 62 = x + 8

m^{2} - 3 m - 4 = 0

3 x^{2} + 12 x - 21 = 0

What are the solutions to the equation 5x^2+15=17x ?
The solutions to the equation 5x^2+15=17x are x= 17/10+i(sqrt(11))/(10),x= 17/10-i(sqrt(11))/(10)
Find the zeros of 5x^2+15=17x
The zeros of 5x^2+15=17x are x= 17/10+i(sqrt(11))/(10),x= 17/10-i(sqrt(11))/(10)