What are the solutions to the equation x^2-22x+121=225 ?

The solutions to the equation x^2-22x+121=225 are x=26,x=-4

Find the zeros of x^2-22x+121=225

The zeros of x^2-22x+121=225 are x=26,x=-4

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x^{2} - 22 x + 121 = 225

x = 26, x = - 4

Solution steps

x^{2} - 22 x + 121 = 225

Move

225

to the left side

x^{2} - 22 x - 104 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 1 \cdot ( - 104 )}{2 \cdot 1}

(- 22)^{2} - 4 \cdot 1 \cdot (- 104) = 30

x_{1, 2} = \frac{- ( - 22 ) \pm 30}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 30}{2 \cdot 1}, x_{2} = \frac{- ( - 22 ) - 30}{2 \cdot 1}

x = \frac{- ( - 22 ) + 30}{2 \cdot 1} : 26

x = \frac{- ( - 22 ) - 30}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 26, x = - 4

- 2 t^{2} + 9 t + 3 = - 6 t^{2}

(x - 10)^{2} = 25

25 x^{2} = 9

4 x^{2} - 12 x + 9 = 9

12 x^{2} - 2 x - 4 = 0

What are the solutions to the equation x^2-22x+121=225 ?
The solutions to the equation x^2-22x+121=225 are x=26,x=-4
Find the zeros of x^2-22x+121=225
The zeros of x^2-22x+121=225 are x=26,x=-4