What are the solutions to the equation 14x^2-72x+64=0 ?

The solutions to the equation 14x^2-72x+64=0 are x=4,x= 8/7

Find the zeros of 14x^2-72x+64=0

The zeros of 14x^2-72x+64=0 are x=4,x= 8/7

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14 x^{2} - 72 x + 64 = 0

x = 4, x = \frac{8}{7}

Decimal Notation

x = 4, x = 1.14285 \dots

Solution steps

14 x^{2} - 72 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 14 \cdot 64}{2 \cdot 14}

(- 72)^{2} - 4 \cdot 14 \cdot 64 = 40

x_{1, 2} = \frac{- ( - 72 ) \pm 40}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 72 ) + 40}{2 \cdot 14}, x_{2} = \frac{- ( - 72 ) - 40}{2 \cdot 14}

x = \frac{- ( - 72 ) + 40}{2 \cdot 14} : 4

x = \frac{- ( - 72 ) - 40}{2 \cdot 14} : \frac{8}{7}

The solutions to the quadratic equation are:

x = 4, x = \frac{8}{7}

x^{2} + 5 x - 204 = 0

(y + 4)^{2} = (4 - y) (4 + y)

x^{2} - 5 x + 3

x^{2} + 19 x + 90 = 0

x^{2} - 6 x + 5 = 0

What are the solutions to the equation 14x^2-72x+64=0 ?
The solutions to the equation 14x^2-72x+64=0 are x=4,x= 8/7
Find the zeros of 14x^2-72x+64=0
The zeros of 14x^2-72x+64=0 are x=4,x= 8/7