What are the solutions to the equation x^2+19x+90=0 ?

The solutions to the equation x^2+19x+90=0 are x=-9,x=-10

Find the zeros of x^2+19x+90=0

The zeros of x^2+19x+90=0 are x=-9,x=-10

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x^{2} + 19 x + 90 = 0

x = - 9, x = - 10

Solution steps

x^{2} + 19 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

1 9^{2} - 4 \cdot 1 \cdot 90 = 1

x_{1, 2} = \frac{- 19 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 19 + 1}{2 \cdot 1}, x_{2} = \frac{- 19 - 1}{2 \cdot 1}

x = \frac{- 19 + 1}{2 \cdot 1} : - 9

x = \frac{- 19 - 1}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 9, x = - 10

x^{2} - 6 x + 5 = 0

x (x + 2) + 2 = 0

8 x^{2} - 7 x = 0

6 x^{2} + 3 x - 5 = 0

9 x^{2} + 10 = 12 x

What are the solutions to the equation x^2+19x+90=0 ?
The solutions to the equation x^2+19x+90=0 are x=-9,x=-10
Find the zeros of x^2+19x+90=0
The zeros of x^2+19x+90=0 are x=-9,x=-10