What are the solutions to the equation 6x^2+3x-5=0 ?

The solutions to the equation 6x^2+3x-5=0 are x=(-3+sqrt(129))/(12),x=(-3-sqrt(129))/(12)

Find the zeros of 6x^2+3x-5=0

The zeros of 6x^2+3x-5=0 are x=(-3+sqrt(129))/(12),x=(-3-sqrt(129))/(12)

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6 x^{2} + 3 x - 5 = 0

x = \frac{- 3 + 129}{12}, x = \frac{- 3 - 129}{12}

Decimal Notation

x = 0.6964847243, x = - 1.19648 \dots

Solution steps

6 x^{2} + 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

3^{2} - 4 \cdot 6 (- 5) = 129

x_{1, 2} = \frac{- 3 \pm 129}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 3 + 129}{2 \cdot 6}, x_{2} = \frac{- 3 - 129}{2 \cdot 6}

x = \frac{- 3 + 129}{2 \cdot 6} : \frac{- 3 + 129}{12}

x = \frac{- 3 - 129}{2 \cdot 6} : \frac{- 3 - 129}{12}

The solutions to the quadratic equation are:

x = \frac{- 3 + 129}{12}, x = \frac{- 3 - 129}{12}

9 x^{2} + 10 = 12 x

x^{2} - 18 x - 2 = 0

2 x^{2} - 12 x + 23

v, m g h = \frac{1}{2} m v^{2}

9 x - 2 = - 5 x^{2}

What are the solutions to the equation 6x^2+3x-5=0 ?
The solutions to the equation 6x^2+3x-5=0 are x=(-3+sqrt(129))/(12),x=(-3-sqrt(129))/(12)
Find the zeros of 6x^2+3x-5=0
The zeros of 6x^2+3x-5=0 are x=(-3+sqrt(129))/(12),x=(-3-sqrt(129))/(12)