What are the solutions to the equation 4(x-2)^2=-1 ?

The solutions to the equation 4(x-2)^2=-1 are x=2+i 1/2 ,x=2-i 1/2

Find the zeros of 4(x-2)^2=-1

The zeros of 4(x-2)^2=-1 are x=2+i 1/2 ,x=2-i 1/2

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4 (x - 2)^{2} = - 1

x = 2 + i \frac{1}{2}, x = 2 - i \frac{1}{2}

Solution steps

4 (x - 2)^{2} = - 1

Divide both sides by

4

(x - 2)^{2} = - \frac{1}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - \frac{1}{4} : x = 2 + i \frac{1}{2}

Solve

x - 2 = - - \frac{1}{4} : x = 2 - i \frac{1}{2}

The solutions to the quadratic equation are:

x = 2 + i \frac{1}{2}, x = 2 - i \frac{1}{2}

2 x^{2} = 22

2 x^{2} = 7 x

3 x^{2} - 30 x - 72 = 0

- 39 = - 8 x^{2} - 7

2 x^{2} - 17 x + 30 = 0

What are the solutions to the equation 4(x-2)^2=-1 ?
The solutions to the equation 4(x-2)^2=-1 are x=2+i 1/2 ,x=2-i 1/2
Find the zeros of 4(x-2)^2=-1
The zeros of 4(x-2)^2=-1 are x=2+i 1/2 ,x=2-i 1/2