What are the solutions to the equation 2x^2=22 ?

The solutions to the equation 2x^2=22 are x=sqrt(11),x=-sqrt(11)

Find the zeros of 2x^2=22

The zeros of 2x^2=22 are x=sqrt(11),x=-sqrt(11)

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2 x^{2} = 22

x = 11, x = - 11

Decimal Notation

x = 3.31662 \dots, x = - 3.31662 \dots

Solution steps

2 x^{2} = 22

Divide both sides by

2

x^{2} = 11

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 11, x = - 11

2 x^{2} = 7 x

3 x^{2} - 30 x - 72 = 0

- 39 = - 8 x^{2} - 7

2 x^{2} - 17 x + 30 = 0

(x - 4)^{2} = 7

What are the solutions to the equation 2x^2=22 ?
The solutions to the equation 2x^2=22 are x=sqrt(11),x=-sqrt(11)
Find the zeros of 2x^2=22
The zeros of 2x^2=22 are x=sqrt(11),x=-sqrt(11)