What are the solutions to the equation y^2=-4y ?

The solutions to the equation y^2=-4y are y=0,y=-4

Find the zeros of y^2=-4y

The zeros of y^2=-4y are y=0,y=-4

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y^{2} = - 4 y

y = 0, y = - 4

Solution steps

y^{2} = - 4 y

Move

4 y

to the left side

y^{2} + 4 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

y_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 4 + 4}{2 \cdot 1}, y_{2} = \frac{- 4 - 4}{2 \cdot 1}

y = \frac{- 4 + 4}{2 \cdot 1} : 0

y = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

y = 0, y = - 4

8 x^{2} - 16 x = 0

2 x^{2} + 6 x = 80

5 q^{2} + q - 1 = 0

x^{2} - 9 x - 8 = 0

y^{2} - 6 y + 7 = 0

What are the solutions to the equation y^2=-4y ?
The solutions to the equation y^2=-4y are y=0,y=-4
Find the zeros of y^2=-4y
The zeros of y^2=-4y are y=0,y=-4