What are the solutions to the equation t^2+1=0 ?

The solutions to the equation t^2+1=0 are t=i,t=-i

Find the zeros of t^2+1=0

The zeros of t^2+1=0 are t=i,t=-i

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t^{2} + 1 = 0

t = i, t = - i

Solution steps

t^{2} + 1 = 0

Move

1

to the right side

t^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - 1, t = - - 1

- 1 = i

- - 1 = - i

t = i, t = - i

(5 x - 3)^{2} = 49

p^{2} + 14 p - 38 = 0

x^{2} + 5 x - 8 = 0

x^{2} + 15 x + 15 = 2 + x

x^{2} - 75 = 0

What are the solutions to the equation t^2+1=0 ?
The solutions to the equation t^2+1=0 are t=i,t=-i
Find the zeros of t^2+1=0
The zeros of t^2+1=0 are t=i,t=-i