What are the solutions to the equation m^2+2m+4=0 ?

The solutions to the equation m^2+2m+4=0 are m=-1+sqrt(3)i,m=-1-sqrt(3)i

Find the zeros of m^2+2m+4=0

The zeros of m^2+2m+4=0 are m=-1+sqrt(3)i,m=-1-sqrt(3)i

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m^{2} + 2 m + 4 = 0

m = - 1 + 3 i, m = - 1 - 3 i

Solution steps

m^{2} + 2 m + 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 4 : 23 i

m_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 2 3 i}{2 \cdot 1}, m_{2} = \frac{- 2 - 2 3 i}{2 \cdot 1}

m = \frac{- 2 + 2 3 i}{2 \cdot 1} : - 1 + 3 i

m = \frac{- 2 - 2 3 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

m = - 1 + 3 i, m = - 1 - 3 i

- x^{2} + 4 x

y, x = 2 y - y^{2}

x^{2} + (x + 1)^{2} = (x - 1) (x + 2)

4 x^{2} - 4 x - 11 = - 8

4 x^{2} - 4 x + 2 = 0

What are the solutions to the equation m^2+2m+4=0 ?
The solutions to the equation m^2+2m+4=0 are m=-1+sqrt(3)i,m=-1-sqrt(3)i
Find the zeros of m^2+2m+4=0
The zeros of m^2+2m+4=0 are m=-1+sqrt(3)i,m=-1-sqrt(3)i