What are the solutions to the equation x^2=2x^2+4 ?

The solutions to the equation x^2=2x^2+4 are x=2i,x=-2i

Find the zeros of x^2=2x^2+4

The zeros of x^2=2x^2+4 are x=2i,x=-2i

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x^{2} = 2 x^{2} + 4

x = 2 i, x = - 2 i

Solution steps

x^{2} = 2 x^{2} + 4

Move

2 x^{2}

to the left side

- x^{2} = 4

Divide both sides by

- 1

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

3 x^{2} + 12 x + 5 = 0

9 x^{2} + 24 x + 16 = 36

r, r^{2} = x^{2} + y^{2}

3 x^{2} + 11 x + 11 = 0

x^{2} - 6 x + 4 = 0

What are the solutions to the equation x^2=2x^2+4 ?
The solutions to the equation x^2=2x^2+4 are x=2i,x=-2i
Find the zeros of x^2=2x^2+4
The zeros of x^2=2x^2+4 are x=2i,x=-2i