What are the solutions to the equation 3x^2+12x+5=0 ?

The solutions to the equation 3x^2+12x+5=0 are x=(-6+sqrt(21))/3 ,x=-(6+sqrt(21))/3

Find the zeros of 3x^2+12x+5=0

The zeros of 3x^2+12x+5=0 are x=(-6+sqrt(21))/3 ,x=-(6+sqrt(21))/3

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3 x^{2} + 12 x + 5 = 0

x = \frac{- 6 + 21}{3}, x = - \frac{6 + 21}{3}

Decimal Notation

x = - 0.47247 \dots, x = - 3.52752 \dots

Solution steps

3 x^{2} + 12 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 \cdot 5 = 221

x_{1, 2} = \frac{- 12 \pm 2 21}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 2 21}{2 \cdot 3}, x_{2} = \frac{- 12 - 2 21}{2 \cdot 3}

x = \frac{- 12 + 2 21}{2 \cdot 3} : \frac{- 6 + 21}{3}

x = \frac{- 12 - 2 21}{2 \cdot 3} : - \frac{6 + 21}{3}

The solutions to the quadratic equation are:

x = \frac{- 6 + 21}{3}, x = - \frac{6 + 21}{3}

9 x^{2} + 24 x + 16 = 36

r, r^{2} = x^{2} + y^{2}

3 x^{2} + 11 x + 11 = 0

x^{2} - 6 x + 4 = 0

2 (x + 2)^{2} - (x - 1)^{2} = 2 x + 7

What are the solutions to the equation 3x^2+12x+5=0 ?
The solutions to the equation 3x^2+12x+5=0 are x=(-6+sqrt(21))/3 ,x=-(6+sqrt(21))/3
Find the zeros of 3x^2+12x+5=0
The zeros of 3x^2+12x+5=0 are x=(-6+sqrt(21))/3 ,x=-(6+sqrt(21))/3