What are the solutions to the equation -3x^2+12x-120=0 ?

The solutions to the equation -3x^2+12x-120=0 are x=2-6i,x=2+6i

Find the zeros of -3x^2+12x-120=0

The zeros of -3x^2+12x-120=0 are x=2-6i,x=2+6i

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- 3 x^{2} + 12 x - 120 = 0

x = 2 - 6 i, x = 2 + 6 i

Solution steps

- 3 x^{2} + 12 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 3 ) ( - 120 )}{2 ( - 3 )}

Simplify

1 2^{2} - 4 (- 3) (- 120) : 36 i

x_{1, 2} = \frac{- 12 \pm 36 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 12 + 36 i}{2 ( - 3 )}, x_{2} = \frac{- 12 - 36 i}{2 ( - 3 )}

x = \frac{- 12 + 36 i}{2 ( - 3 )} : 2 - 6 i

x = \frac{- 12 - 36 i}{2 ( - 3 )} : 2 + 6 i

The solutions to the quadratic equation are:

x = 2 - 6 i, x = 2 + 6 i

x^{2} + 4 x - 285 = 0

4 (3 x + 4)^{2} - 40 = - 24

a^{2} + 6 a + 4 = 0

25 x^{2} = 20 x - 4

- 19 = - 3 - n^{2}

What are the solutions to the equation -3x^2+12x-120=0 ?
The solutions to the equation -3x^2+12x-120=0 are x=2-6i,x=2+6i
Find the zeros of -3x^2+12x-120=0
The zeros of -3x^2+12x-120=0 are x=2-6i,x=2+6i