What are the solutions to the equation -3x^2+2x+4=-x-3 ?

The solutions to the equation -3x^2+2x+4=-x-3 are x=-(-3+sqrt(93))/6 ,x=(3+sqrt(93))/6

Find the zeros of -3x^2+2x+4=-x-3

The zeros of -3x^2+2x+4=-x-3 are x=-(-3+sqrt(93))/6 ,x=(3+sqrt(93))/6

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- 3 x^{2} + 2 x + 4 = - x - 3

x = - \frac{- 3 + 93}{6}, x = \frac{3 + 93}{6}

Decimal Notation

x = - 1.10727 \dots, x = 2.10727 \dots

Solution steps

- 3 x^{2} + 2 x + 4 = - x - 3

Move

3

to the left side

- 3 x^{2} + 2 x + 7 = - x

Move

x

to the left side

- 3 x^{2} + 3 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 3 ) \cdot 7}{2 ( - 3 )}

3^{2} - 4 (- 3) \cdot 7 = 93

x_{1, 2} = \frac{- 3 \pm 93}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 3 + 93}{2 ( - 3 )}, x_{2} = \frac{- 3 - 93}{2 ( - 3 )}

x = \frac{- 3 + 93}{2 ( - 3 )} : - \frac{- 3 + 93}{6}

x = \frac{- 3 - 93}{2 ( - 3 )} : \frac{3 + 93}{6}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 93}{6}, x = \frac{3 + 93}{6}

- 4 m^{2} + 2 m - 11 = - 5 m^{2}

- 12 x^{2} - 92 x - 56 = 0

2 x^{2} - 7 x + 12 = 0

3 x^{2} - (2 m + 12) x + 216 = 0

x^{2} - \frac{1}{2} x - \frac{1}{2} = 0

What are the solutions to the equation -3x^2+2x+4=-x-3 ?
The solutions to the equation -3x^2+2x+4=-x-3 are x=-(-3+sqrt(93))/6 ,x=(3+sqrt(93))/6
Find the zeros of -3x^2+2x+4=-x-3
The zeros of -3x^2+2x+4=-x-3 are x=-(-3+sqrt(93))/6 ,x=(3+sqrt(93))/6