What are the solutions to the equation 4x^2-16x+25=0 ?

The solutions to the equation 4x^2-16x+25=0 are x=2+i 3/2 ,x=2-i 3/2

Find the zeros of 4x^2-16x+25=0

The zeros of 4x^2-16x+25=0 are x=2+i 3/2 ,x=2-i 3/2

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4 x^{2} - 16 x + 25 = 0

x = 2 + i \frac{3}{2}, x = 2 - i \frac{3}{2}

Solution steps

4 x^{2} - 16 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

Simplify

(- 16)^{2} - 4 \cdot 4 \cdot 25 : 12 i

x_{1, 2} = \frac{- ( - 16 ) \pm 12 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 12 i}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 12 i}{2 \cdot 4}

x = \frac{- ( - 16 ) + 12 i}{2 \cdot 4} : 2 + i \frac{3}{2}

x = \frac{- ( - 16 ) - 12 i}{2 \cdot 4} : 2 - i \frac{3}{2}

The solutions to the quadratic equation are:

x = 2 + i \frac{3}{2}, x = 2 - i \frac{3}{2}

x^{2} - 15 x + 56.25 = 8

x^{2} + \frac{x}{3} = \frac{2}{3}

72 - 6 x^{2} = 0

- 34 = x^{2} - 14 x + 10

16 x^{2} = 24 x - 11

What are the solutions to the equation 4x^2-16x+25=0 ?
The solutions to the equation 4x^2-16x+25=0 are x=2+i 3/2 ,x=2-i 3/2
Find the zeros of 4x^2-16x+25=0
The zeros of 4x^2-16x+25=0 are x=2+i 3/2 ,x=2-i 3/2