What are the solutions to the equation x^2+x/3 = 2/3 ?

The solutions to the equation x^2+x/3 = 2/3 are x= 2/3 ,x=-1

Find the zeros of x^2+x/3 = 2/3

The zeros of x^2+x/3 = 2/3 are x= 2/3 ,x=-1

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x^{2} + \frac{x}{3} = \frac{2}{3}

x = \frac{2}{3}, x = - 1

Decimal Notation

x = 0.66666 \dots, x = - 1

Solution steps

x^{2} + \frac{x}{3} = \frac{2}{3}

Multiply both sides by

3

3 x^{2} + x = 2

Move

2

to the left side

3 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 2) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 3}, x_{2} = \frac{- 1 - 5}{2 \cdot 3}

x = \frac{- 1 + 5}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 1 - 5}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 1

72 - 6 x^{2} = 0

- 34 = x^{2} - 14 x + 10

16 x^{2} = 24 x - 11

- x^{2} + 600 x - 90 = 0

- 3 x^{2} - 54 x - 96 = 0

What are the solutions to the equation x^2+x/3 = 2/3 ?
The solutions to the equation x^2+x/3 = 2/3 are x= 2/3 ,x=-1
Find the zeros of x^2+x/3 = 2/3
The zeros of x^2+x/3 = 2/3 are x= 2/3 ,x=-1