What are the solutions to the equation completesquare x^2+4x+1=0 ?

The solutions to the equation completesquare x^2+4x+1=0 are x=sqrt(3)-2,x=-sqrt(3)-2

Find the zeros of completesquare x^2+4x+1=0

The zeros of completesquare x^2+4x+1=0 are x=sqrt(3)-2,x=-sqrt(3)-2

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x^{2} + 4 x + 1 = 0

x = 3 - 2, x = - 3 - 2

Decimal Notation

x = - 0.26794 \dots, x = - 3.73205 \dots

Solution steps

x^{2} + 4 x + 1 = 0

Move

1

to the right side

x^{2} + 4 x = - 1

Rewrite in the form

(x + a)^{2} = b

(x + 2)^{2} = 3

For

the solutions are

f (x) = a, - a

Solve

x + 2 = 3 : x = 3 - 2

Solve

x + 2 = - 3 : x = - 3 - 2

The solutions to the quadratic equation are:

x = 3 - 2, x = - 3 - 2

x^{2} + x + 1 = 0

5 n^{2} - 14 n - 12 = 0

x^{2} + 7 x + 10 = 0

3 n^{2} + 16 n + 15 = 1

4 x^{2} + 5 = - 12 x

What are the solutions to the equation completesquare x^2+4x+1=0 ?
The solutions to the equation completesquare x^2+4x+1=0 are x=sqrt(3)-2,x=-sqrt(3)-2
Find the zeros of completesquare x^2+4x+1=0
The zeros of completesquare x^2+4x+1=0 are x=sqrt(3)-2,x=-sqrt(3)-2