What are the solutions to the equation 9(2x-3)^2=16 ?

The solutions to the equation 9(2x-3)^2=16 are x= 13/6 ,x= 5/6

Find the zeros of 9(2x-3)^2=16

The zeros of 9(2x-3)^2=16 are x= 13/6 ,x= 5/6

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9 (2 x - 3)^{2} = 16

x = \frac{13}{6}, x = \frac{5}{6}

Decimal Notation

x = 2.16666 \dots, x = 0.83333 \dots

Solution steps

9 (2 x - 3)^{2} = 16

Divide both sides by

9

(2 x - 3)^{2} = \frac{16}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = \frac{16}{9} : x = \frac{13}{6}

Solve

2 x - 3 = - \frac{16}{9} : x = \frac{5}{6}

The solutions to the quadratic equation are:

x = \frac{13}{6}, x = \frac{5}{6}

x^{2} - 19 x = 9.75

3 x^{2} - 13 x + 10 = 0

x^{2} - 19 x + 48 = 0

r, A = 2 π r (r + h)

3 w^{2} + 15 w + 12 = w

What are the solutions to the equation 9(2x-3)^2=16 ?
The solutions to the equation 9(2x-3)^2=16 are x= 13/6 ,x= 5/6
Find the zeros of 9(2x-3)^2=16
The zeros of 9(2x-3)^2=16 are x= 13/6 ,x= 5/6