What are the solutions to the equation (x+2)(x-5)=6-3x ?

The solutions to the equation (x+2)(x-5)=6-3x are x=4,x=-4

Find the zeros of (x+2)(x-5)=6-3x

The zeros of (x+2)(x-5)=6-3x are x=4,x=-4

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(x + 2) (x - 5) = 6 - 3 x

x = 4, x = - 4

Solution steps

(x + 2) (x - 5) = 6 - 3 x

Expand

(x + 2) (x - 5) : x^{2} - 3 x - 10

x^{2} - 3 x - 10 = 6 - 3 x

Move

10

to the right side

x^{2} - 3 x = - 3 x + 16

Move

3 x

to the left side

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

x^{2} - 4 x + 8

x^{2} - 4 x + 1

x, x^{2} + x y - y^{2} = 4

- 5 (x + 4) (3 x - 7) = - (x + 4) 10

4 v^{2} + 7 v - 7 = 0

What are the solutions to the equation (x+2)(x-5)=6-3x ?
The solutions to the equation (x+2)(x-5)=6-3x are x=4,x=-4
Find the zeros of (x+2)(x-5)=6-3x
The zeros of (x+2)(x-5)=6-3x are x=4,x=-4