What are the solutions to the equation (3x-5)*(5x-6)=0 ?

The solutions to the equation (3x-5)*(5x-6)=0 are x= 5/3 ,x= 6/5

Find the zeros of (3x-5)*(5x-6)=0

The zeros of (3x-5)*(5x-6)=0 are x= 5/3 ,x= 6/5

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(3 x - 5) \cdot (5 x - 6) = 0

x = \frac{5}{3}, x = \frac{6}{5}

Decimal Notation

x = 1.66666 \dots, x = 1.2

Solution steps

(3 x - 5) (5 x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 5 = 0 or 5 x - 6 = 0

Solve

3 x - 5 = 0 : x = \frac{5}{3}

Solve

5 x - 6 = 0 : x = \frac{6}{5}

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = \frac{6}{5}

- 10 x^{2} + 13 x + 3

j^{2} + 9 j + 14

(x^{2} - 2 x - 1) = 0

3 x^{2} = 4

ln (9 x)

What are the solutions to the equation (3x-5)*(5x-6)=0 ?
The solutions to the equation (3x-5)*(5x-6)=0 are x= 5/3 ,x= 6/5
Find the zeros of (3x-5)*(5x-6)=0
The zeros of (3x-5)*(5x-6)=0 are x= 5/3 ,x= 6/5