What are the solutions to the equation (x^2-2x-1)=0 ?

The solutions to the equation (x^2-2x-1)=0 are x=1+sqrt(2),x=1-sqrt(2)

Find the zeros of (x^2-2x-1)=0

The zeros of (x^2-2x-1)=0 are x=1+sqrt(2),x=1-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^{2} - 2 x - 1) = 0

x = 1 + 2, x = 1 - 2

Decimal Notation

x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

(x^{2} - 2 x - 1) = 0

Refine

x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 1) = 22

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 2}{2 \cdot 1} : 1 + 2

x = \frac{- ( - 2 ) - 2 2}{2 \cdot 1} : 1 - 2

The solutions to the quadratic equation are:

x = 1 + 2, x = 1 - 2

3 x^{2} = 4

ln (9 x)

- 2 x^{2} + x + 8 = 0

4 x^{2} - x - 14

(- \frac{9}{8})^{2}

What are the solutions to the equation (x^2-2x-1)=0 ?
The solutions to the equation (x^2-2x-1)=0 are x=1+sqrt(2),x=1-sqrt(2)
Find the zeros of (x^2-2x-1)=0
The zeros of (x^2-2x-1)=0 are x=1+sqrt(2),x=1-sqrt(2)