What are the solutions to the equation -x^2+5x+25=0 ?

The solutions to the equation -x^2+5x+25=0 are x=-(-5+5sqrt(5))/2 ,x=(5+5sqrt(5))/2

Find the zeros of -x^2+5x+25=0

The zeros of -x^2+5x+25=0 are x=-(-5+5sqrt(5))/2 ,x=(5+5sqrt(5))/2

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- x^{2} + 5 x + 25 = 0

x = - \frac{- 5 + 5 5}{2}, x = \frac{5 + 5 5}{2}

Decimal Notation

x = - 3.09016 \dots, x = 8.09016 \dots

Solution steps

- x^{2} + 5 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 25}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 25 = 55

x_{1, 2} = \frac{- 5 \pm 5 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 5 5}{2 ( - 1 )}, x_{2} = \frac{- 5 - 5 5}{2 ( - 1 )}

x = \frac{- 5 + 5 5}{2 ( - 1 )} : - \frac{- 5 + 5 5}{2}

x = \frac{- 5 - 5 5}{2 ( - 1 )} : \frac{5 + 5 5}{2}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 5 5}{2}, x = \frac{5 + 5 5}{2}

4 x^{2} - 12 x + 1 = 0

3 x^{2} + 33 x + 30 = 0

a^{2} - 3 a + 2 = 0

x^{2} + 15 x = 5 x - 24

25 (x^{2} - 5) + 14 = 10

What are the solutions to the equation -x^2+5x+25=0 ?
The solutions to the equation -x^2+5x+25=0 are x=-(-5+5sqrt(5))/2 ,x=(5+5sqrt(5))/2
Find the zeros of -x^2+5x+25=0
The zeros of -x^2+5x+25=0 are x=-(-5+5sqrt(5))/2 ,x=(5+5sqrt(5))/2