What are the solutions to the equation x(x-2)+x-2=0 ?

The solutions to the equation x(x-2)+x-2=0 are x=2,x=-1

Find the zeros of x(x-2)+x-2=0

The zeros of x(x-2)+x-2=0 are x=2,x=-1

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x (x - 2) + x - 2 = 0

x = 2, x = - 1

Solution steps

x (x - 2) + x - 2 = 0

Expand

x (x - 2) + x - 2 : x^{2} - x - 2

x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

x = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

x^{2} - 2 x + 13 = 0

x^{2} - 5 x + 6 = 0

5 x^{2} + 20 x + 16 = 0

x^{2} - (3 + 5) x + 4 = 0

t^{2} - 2 t = 0

What are the solutions to the equation x(x-2)+x-2=0 ?
The solutions to the equation x(x-2)+x-2=0 are x=2,x=-1
Find the zeros of x(x-2)+x-2=0
The zeros of x(x-2)+x-2=0 are x=2,x=-1