What are the solutions to the equation 5-3(2x+1)^2=-22 ?

The solutions to the equation 5-3(2x+1)^2=-22 are x=1,x=-2

Find the zeros of 5-3(2x+1)^2=-22

The zeros of 5-3(2x+1)^2=-22 are x=1,x=-2

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5 - 3 (2 x + 1)^{2} = - 22

x = 1, x = - 2

Solution steps

5 - 3 (2 x + 1)^{2} = - 22

Move

5

to the right side

- 3 (2 x + 1)^{2} = - 27

Divide both sides by

- 3

(2 x + 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 1 = 9 : x = 1

Solve

2 x + 1 = - 9 : x = - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

x^{2} + 5 x = 84

- 2 x^{2} - 5 x + 7 = 0

(x + 1) (x - 2) = 0

s^{2} + s - 2 = 0

3 x^{2} + 12 x + 15 = 0

What are the solutions to the equation 5-3(2x+1)^2=-22 ?
The solutions to the equation 5-3(2x+1)^2=-22 are x=1,x=-2
Find the zeros of 5-3(2x+1)^2=-22
The zeros of 5-3(2x+1)^2=-22 are x=1,x=-2