What are the solutions to the equation 3x^2+12x+15=0 ?

The solutions to the equation 3x^2+12x+15=0 are x=-2+i,x=-2-i

Find the zeros of 3x^2+12x+15=0

The zeros of 3x^2+12x+15=0 are x=-2+i,x=-2-i

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3 x^{2} + 12 x + 15 = 0

x = - 2 + i, x = - 2 - i

Solution steps

3 x^{2} + 12 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 15}{2 \cdot 3}

Simplify

1 2^{2} - 4 \cdot 3 \cdot 15 : 6 i

x_{1, 2} = \frac{- 12 \pm 6 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 6 i}{2 \cdot 3}, x_{2} = \frac{- 12 - 6 i}{2 \cdot 3}

x = \frac{- 12 + 6 i}{2 \cdot 3} : - 2 + i

x = \frac{- 12 - 6 i}{2 \cdot 3} : - 2 - i

The solutions to the quadratic equation are:

x = - 2 + i, x = - 2 - i

y^{2} + 10 y + 25 = 0

(x - 6) (x + 9) = 0

2^{2} = 1^{2} + x^{2}

x, f = 2 x^{2} + x y + y^{2} + 100 - z (x + y - 100)

x^{2} - 5 x - 14 = 0

What are the solutions to the equation 3x^2+12x+15=0 ?
The solutions to the equation 3x^2+12x+15=0 are x=-2+i,x=-2-i
Find the zeros of 3x^2+12x+15=0
The zeros of 3x^2+12x+15=0 are x=-2+i,x=-2-i