What are the solutions to the equation y^2+10y+25=0 ?

The solutions to the equation y^2+10y+25=0 are y=-5

Find the zeros of y^2+10y+25=0

The zeros of y^2+10y+25=0 are y=-5

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y^{2} + 10 y + 25 = 0

y = - 5

Solution steps

y^{2} + 10 y + 25 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

y_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

y = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

y = - 5

The solution to the quadratic equation is:

y = - 5

(x - 6) (x + 9) = 0

2^{2} = 1^{2} + x^{2}

x, f = 2 x^{2} + x y + y^{2} + 100 - z (x + y - 100)

x^{2} - 5 x - 14 = 0

(2 x + 1) (x + 1) = (x + 2) (x - 2) + 3

What are the solutions to the equation y^2+10y+25=0 ?
The solutions to the equation y^2+10y+25=0 are y=-5
Find the zeros of y^2+10y+25=0
The zeros of y^2+10y+25=0 are y=-5