What are the solutions to the equation 16(7-3x)^2+13=17 ?

The solutions to the equation 16(7-3x)^2+13=17 are x= 13/6 ,x= 5/2

Find the zeros of 16(7-3x)^2+13=17

The zeros of 16(7-3x)^2+13=17 are x= 13/6 ,x= 5/2

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16 (7 - 3 x)^{2} + 13 = 17

x = \frac{13}{6}, x = \frac{5}{2}

Decimal Notation

x = 2.16666 \dots, x = 2.5

Solution steps

16 (7 - 3 x)^{2} + 13 = 17

Move

13

to the right side

16 (7 - 3 x)^{2} = 4

Divide both sides by

16

(7 - 3 x)^{2} = \frac{1}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 - 3 x = \frac{1}{4} : x = \frac{13}{6}

Solve

7 - 3 x = - \frac{1}{4} : x = \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{13}{6}, x = \frac{5}{2}

a^{2} + 15 a + 56 = 0

2 x^{2} - 30 x = 3500

- 2 x^{2} - x + 6 = 0

x^{2} + 3 x - 10 = 0

x^{2} - 6 = 10

What are the solutions to the equation 16(7-3x)^2+13=17 ?
The solutions to the equation 16(7-3x)^2+13=17 are x= 13/6 ,x= 5/2
Find the zeros of 16(7-3x)^2+13=17
The zeros of 16(7-3x)^2+13=17 are x= 13/6 ,x= 5/2