What are the solutions to the equation (2x+3)^2+5=8 ?

The solutions to the equation (2x+3)^2+5=8 are x=(sqrt(3)-3)/2 ,x=(-sqrt(3)-3)/2

Find the zeros of (2x+3)^2+5=8

The zeros of (2x+3)^2+5=8 are x=(sqrt(3)-3)/2 ,x=(-sqrt(3)-3)/2

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(2 x + 3)^{2} + 5 = 8

x = \frac{3 - 3}{2}, x = \frac{- 3 - 3}{2}

Decimal Notation

x = - 0.63397 \dots, x = - 2.36602 \dots

Solution steps

(2 x + 3)^{2} + 5 = 8

Move

5

to the right side

(2 x + 3)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 = 3 : x = \frac{3 - 3}{2}

Solve

2 x + 3 = - 3 : x = \frac{- 3 - 3}{2}

The solutions to the quadratic equation are:

x = \frac{3 - 3}{2}, x = \frac{- 3 - 3}{2}

x^{2} + x = 3

x, x^{2} - 3 k x + 3 k - 7 = 0

(x + 5) (x + 2) = 0

3 x^{2} + 7 = 301

x^{2} + 7 x = 68.75

What are the solutions to the equation (2x+3)^2+5=8 ?
The solutions to the equation (2x+3)^2+5=8 are x=(sqrt(3)-3)/2 ,x=(-sqrt(3)-3)/2
Find the zeros of (2x+3)^2+5=8
The zeros of (2x+3)^2+5=8 are x=(sqrt(3)-3)/2 ,x=(-sqrt(3)-3)/2