What are the solutions to the equation -5x-2=-2x^2-2x ?

The solutions to the equation -5x-2=-2x^2-2x are x=-1/2 ,x=2

Find the zeros of -5x-2=-2x^2-2x

The zeros of -5x-2=-2x^2-2x are x=-1/2 ,x=2

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- 5 x - 2 = - 2 x^{2} - 2 x

x = - \frac{1}{2}, x = 2

Decimal Notation

x = - 0.5, x = 2

Solution steps

- 5 x - 2 = - 2 x^{2} - 2 x

Switch sides

- 2 x^{2} - 2 x = - 5 x - 2

Move

2

to the left side

- 2 x^{2} - 2 x + 2 = - 5 x

Move

5 x

to the left side

- 2 x^{2} + 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) \cdot 2}{2 ( - 2 )}

3^{2} - 4 (- 2) \cdot 2 = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 ( - 2 )}, x_{2} = \frac{- 3 - 5}{2 ( - 2 )}

x = \frac{- 3 + 5}{2 ( - 2 )} : - \frac{1}{2}

x = \frac{- 3 - 5}{2 ( - 2 )} : 2

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 2

x^{2} + 10 x = 3

x^{2} - 4 x + 4

x, y^{4} = y^{2} - x^{2}

4 x^{2} = 5 x + 8

(x + 5) (x + 7) = 0

What are the solutions to the equation -5x-2=-2x^2-2x ?
The solutions to the equation -5x-2=-2x^2-2x are x=-1/2 ,x=2
Find the zeros of -5x-2=-2x^2-2x
The zeros of -5x-2=-2x^2-2x are x=-1/2 ,x=2